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11x^2-18x-8=0
a = 11; b = -18; c = -8;
Δ = b2-4ac
Δ = -182-4·11·(-8)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-26}{2*11}=\frac{-8}{22} =-4/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+26}{2*11}=\frac{44}{22} =2 $
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