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11x^2-240x-44=0
a = 11; b = -240; c = -44;
Δ = b2-4ac
Δ = -2402-4·11·(-44)
Δ = 59536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{59536}=244$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-244}{2*11}=\frac{-4}{22} =-2/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+244}{2*11}=\frac{484}{22} =22 $
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