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11x^2-33x+22=0
a = 11; b = -33; c = +22;
Δ = b2-4ac
Δ = -332-4·11·22
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-11}{2*11}=\frac{22}{22} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+11}{2*11}=\frac{44}{22} =2 $
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