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11x^2-34x+3=0
a = 11; b = -34; c = +3;
Δ = b2-4ac
Δ = -342-4·11·3
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-32}{2*11}=\frac{2}{22} =1/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+32}{2*11}=\frac{66}{22} =3 $
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