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11x^2-49x-30=0
a = 11; b = -49; c = -30;
Δ = b2-4ac
Δ = -492-4·11·(-30)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-61}{2*11}=\frac{-12}{22} =-6/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+61}{2*11}=\frac{110}{22} =5 $
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