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11x^2-68x+12=0
a = 11; b = -68; c = +12;
Δ = b2-4ac
Δ = -682-4·11·12
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-64}{2*11}=\frac{4}{22} =2/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+64}{2*11}=\frac{132}{22} =6 $
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