11x2-8=-6x-9x2

Solution for 11x2-8=-6x-9x2 equation:

11x^2-8=-6x-9x^2

We move all terms to the left:

11x^2-8-(-6x-9x^2)=0

We get rid of parentheses

11x^2+9x^2+6x-8=0

We add all the numbers together, and all the variables

20x^2+6x-8=0

a = 20; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·20·(-8)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-26}{2*20}=\frac{-32}{40}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+26}{2*20}=\frac{20}{40}
=1/2
$