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11x^2-9x=5
We move all terms to the left:
11x^2-9x-(5)=0
a = 11; b = -9; c = -5;
Δ = b2-4ac
Δ = -92-4·11·(-5)
Δ = 301
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{301}}{2*11}=\frac{9-\sqrt{301}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{301}}{2*11}=\frac{9+\sqrt{301}}{22} $
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