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11x^2-x-10=0
We add all the numbers together, and all the variables
11x^2-1x-10=0
a = 11; b = -1; c = -10;
Δ = b2-4ac
Δ = -12-4·11·(-10)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-21}{2*11}=\frac{-20}{22} =-10/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+21}{2*11}=\frac{22}{22} =1 $
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