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11x^2=7-2x
We move all terms to the left:
11x^2-(7-2x)=0
We add all the numbers together, and all the variables
11x^2-(-2x+7)=0
We get rid of parentheses
11x^2+2x-7=0
a = 11; b = 2; c = -7;
Δ = b2-4ac
Δ = 22-4·11·(-7)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{78}}{2*11}=\frac{-2-2\sqrt{78}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{78}}{2*11}=\frac{-2+2\sqrt{78}}{22} $
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