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11x=8x-3x(5-2x)
We move all terms to the left:
11x-(8x-3x(5-2x))=0
We add all the numbers together, and all the variables
11x-(8x-3x(-2x+5))=0
We calculate terms in parentheses: -(8x-3x(-2x+5)), so:We get rid of parentheses
8x-3x(-2x+5)
We multiply parentheses
6x^2+8x-15x
We add all the numbers together, and all the variables
6x^2-7x
Back to the equation:
-(6x^2-7x)
-6x^2+11x+7x=0
We add all the numbers together, and all the variables
-6x^2+18x=0
a = -6; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-6)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-6}=\frac{-36}{-12} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-6}=\frac{0}{-12} =0 $
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