11y(1+2y)=0

Solution for 11y(1+2y)=0 equation:

11y(1+2y)=0

We add all the numbers together, and all the variables

11y(2y+1)=0

We multiply parentheses

22y^2+11y=0

a = 22; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·22·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*22}=\frac{-22}{44}
=-1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*22}=\frac{0}{44}
=0
$