11y+7-3y=2(4y-5)+17

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Solution for 11y+7-3y=2(4y-5)+17 equation: 



11y+7-3y=2(4y-5)+17

We move all terms to the left:

11y+7-3y-(2(4y-5)+17)=0

We add all the numbers together, and all the variables

8y-(2(4y-5)+17)+7=0



We calculate terms in parentheses: -(2(4y-5)+17), so:

2(4y-5)+17

We multiply parentheses

8y-10+17

We add all the numbers together, and all the variables

8y+7

Back to the equation:

-(8y+7)



We get rid of parentheses

8y-8y-7+7=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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