11y-12=11+8(y+3)

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Solution for 11y-12=11+8(y+3) equation: 



11y-12=11+8(y+3)

We move all terms to the left:

11y-12-(11+8(y+3))=0



We calculate terms in parentheses: -(11+8(y+3)), so:

11+8(y+3)

determiningTheFunctionDomain
8(y+3)+11

We multiply parentheses

8y+24+11

We add all the numbers together, and all the variables

8y+35

Back to the equation:

-(8y+35)



We get rid of parentheses

11y-8y-35-12=0

We add all the numbers together, and all the variables

3y-47=0

We move all terms containing y to the left, all other terms to the right

3y=47

y=47/3

y=15+2/3

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