11z+3-42=5z

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Solution for 11z+3-42=5z equation: 



11z+3-42=5z

We move all terms to the left:

11z+3-42-(5z)=0

We add all the numbers together, and all the variables

6z-39=0

We move all terms containing z to the left, all other terms to the right

6z=39

z=39/6

z=6+1/2

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