11z-9=1+7(z+3)

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Solution for 11z-9=1+7(z+3) equation: 



11z-9=1+7(z+3)

We move all terms to the left:

11z-9-(1+7(z+3))=0



We calculate terms in parentheses: -(1+7(z+3)), so:

1+7(z+3)

determiningTheFunctionDomain
7(z+3)+1

We multiply parentheses

7z+21+1

We add all the numbers together, and all the variables

7z+22

Back to the equation:

-(7z+22)



We get rid of parentheses

11z-7z-22-9=0

We add all the numbers together, and all the variables

4z-31=0

We move all terms containing z to the left, all other terms to the right

4z=31

z=31/4

z=7+3/4

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