12((1+2y)/(3))+6y=11

Solution for 12((1+2y)/(3))+6y=11 equation:

12((1+2y)/(3))+6y=11

We move all terms to the left:

12((1+2y)/(3))+6y-(11)=0

We add all the numbers together, and all the variables

12((2y+1)/3)+6y-11=0

We add all the numbers together, and all the variables

6y+12((2y+1)/3)-11=0

We multiply all the terms by the denominator


6y*3)+12((2y+1)-11*3)=0

We add all the numbers together, and all the variables

6y*3)+12((2y+1)=0

Wy multiply elements

18y^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{36}=0$