12(-4b-6)=7b-12(1+5b)

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Solution for 12(-4b-6)=7b-12(1+5b) equation:



12(-4b-6)=7b-12(1+5b)
We move all terms to the left:
12(-4b-6)-(7b-12(1+5b))=0
We add all the numbers together, and all the variables
12(-4b-6)-(7b-12(5b+1))=0
We multiply parentheses
-48b-(7b-12(5b+1))-72=0
We calculate terms in parentheses: -(7b-12(5b+1)), so:
7b-12(5b+1)
We multiply parentheses
7b-60b-12
We add all the numbers together, and all the variables
-53b-12
Back to the equation:
-(-53b-12)
We get rid of parentheses
-48b+53b+12-72=0
We add all the numbers together, and all the variables
5b-60=0
We move all terms containing b to the left, all other terms to the right
5b=60
b=60/5
b=12

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