12(.5y+2)=10(3y-9)

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Solution for 12(.5y+2)=10(3y-9) equation: 



12(.5y+2)=10(3y-9)

We move all terms to the left:

12(.5y+2)-(10(3y-9))=0

We multiply parentheses

12y-(10(3y-9))+24=0



We calculate terms in parentheses: -(10(3y-9)), so:

10(3y-9)

We multiply parentheses

30y-90

Back to the equation:

-(30y-90)



We get rid of parentheses

12y-30y+90+24=0

We add all the numbers together, and all the variables

-18y+114=0

We move all terms containing y to the left, all other terms to the right

-18y=-114

y=-114/-18

y=6+1/3

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