12(1+5v)+4v=12(1+11v)

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Solution for 12(1+5v)+4v=12(1+11v) equation: 



12(1+5v)+4v=12(1+11v)

We move all terms to the left:

12(1+5v)+4v-(12(1+11v))=0

We add all the numbers together, and all the variables

12(5v+1)+4v-(12(11v+1))=0

We add all the numbers together, and all the variables

4v+12(5v+1)-(12(11v+1))=0

We multiply parentheses

4v+60v-(12(11v+1))+12=0



We calculate terms in parentheses: -(12(11v+1)), so:

12(11v+1)

We multiply parentheses

132v+12

Back to the equation:

-(132v+12)



We add all the numbers together, and all the variables

64v-(132v+12)+12=0

We get rid of parentheses

64v-132v-12+12=0

We add all the numbers together, and all the variables

-68v=0

v=0/-68

v=0

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