12(1+b)=2(b-4)

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Solution for 12(1+b)=2(b-4) equation:


Simplifying
12(1 + b) = 2(b + -4)
(1 * 12 + b * 12) = 2(b + -4)
(12 + 12b) = 2(b + -4)

Reorder the terms:
12 + 12b = 2(-4 + b)
12 + 12b = (-4 * 2 + b * 2)
12 + 12b = (-8 + 2b)

Solving
12 + 12b = -8 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
12 + 12b + -2b = -8 + 2b + -2b

Combine like terms: 12b + -2b = 10b
12 + 10b = -8 + 2b + -2b

Combine like terms: 2b + -2b = 0
12 + 10b = -8 + 0
12 + 10b = -8

Add '-12' to each side of the equation.
12 + -12 + 10b = -8 + -12

Combine like terms: 12 + -12 = 0
0 + 10b = -8 + -12
10b = -8 + -12

Combine like terms: -8 + -12 = -20
10b = -20

Divide each side by '10'.
b = -2

Simplifying
b = -2

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