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12(1/2x+2)-5=3(x-6)+1
We move all terms to the left:
12(1/2x+2)-5-(3(x-6)+1)=0
Domain of the equation: 2x+2)!=0We multiply parentheses
x∈R
12x-(3(x-6)+1)+24-5=0
We calculate terms in parentheses: -(3(x-6)+1), so:We add all the numbers together, and all the variables
3(x-6)+1
We multiply parentheses
3x-18+1
We add all the numbers together, and all the variables
3x-17
Back to the equation:
-(3x-17)
12x-(3x-17)+19=0
We get rid of parentheses
12x-3x+17+19=0
We add all the numbers together, and all the variables
9x+36=0
We move all terms containing x to the left, all other terms to the right
9x=-36
x=-36/9
x=-4
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