12(1/3+3)=6(b+9)

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Solution for 12(1/3+3)=6(b+9) equation: 



12(1/3+3)=6(b+9)

We move all terms to the left:

12(1/3+3)-(6(b+9))=0

We multiply parentheses

-(6(b+9))+36+1/3*12=0

We multiply all the terms by the denominator


-((6(b+9)))*3*12+1+36*3*12=0

We add all the numbers together, and all the variables

-((6(b+9)))*3*12+1297=0

We move all terms containing b to the left, all other terms to the right

-((6(b+9)))*3*12=-1297

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