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12(1/y)+3=4
We move all terms to the left:
12(1/y)+3-(4)=0
Domain of the equation: y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
12(+1/y)+3-4=0
We add all the numbers together, and all the variables
12(+1/y)-1=0
We multiply parentheses
12y-1=0
We move all terms containing y to the left, all other terms to the right
12y=1
y=1/12
y=1/12
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