12(10)=(x+6)(x+1)

Solution for 12(10)=(x+6)(x+1) equation:

12(10)=(x+6)(x+1)

We move all terms to the left:

12(10)-((x+6)(x+1))=0

We multiply parentheses ..

-((+x^2+x+6x+6))+1210=0


We calculate terms in parentheses: -((+x^2+x+6x+6)), so:

(+x^2+x+6x+6)

We get rid of parentheses

x^2+x+6x+6

We add all the numbers together, and all the variables

x^2+7x+6

Back to the equation:

-(x^2+7x+6)


We get rid of parentheses

-x^2-7x-6+1210=0

We add all the numbers together, and all the variables

-1x^2-7x+1204=0

a = -1; b = -7; c = +1204;
Δ = b2-4ac
Δ = -72-4·(-1)·1204
Δ = 4865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{4865}}{2*-1}=\frac{7-\sqrt{4865}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{4865}}{2*-1}=\frac{7+\sqrt{4865}}{-2}
$