12(10-8x-6x)+10(10x+16)=38

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Solution for 12(10-8x-6x)+10(10x+16)=38 equation: 



12(10-8x-6x)+10(10x+16)=38

We move all terms to the left:

12(10-8x-6x)+10(10x+16)-(38)=0

We add all the numbers together, and all the variables

12(-14x+10)+10(10x+16)-38=0

We multiply parentheses

-168x+100x+120+160-38=0

We add all the numbers together, and all the variables

-68x+242=0

We move all terms containing x to the left, all other terms to the right

-68x=-242

x=-242/-68

x=3+19/34

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