12(11-x)=3(23+x)

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Solution for 12(11-x)=3(23+x) equation: 



12(11-x)=3(23+x)

We move all terms to the left:

12(11-x)-(3(23+x))=0

We add all the numbers together, and all the variables

12(-1x+11)-(3(x+23))=0

We multiply parentheses

-12x-(3(x+23))+132=0



We calculate terms in parentheses: -(3(x+23)), so:

3(x+23)

We multiply parentheses

3x+69

Back to the equation:

-(3x+69)



We get rid of parentheses

-12x-3x-69+132=0

We add all the numbers together, and all the variables

-15x+63=0

We move all terms containing x to the left, all other terms to the right

-15x=-63

x=-63/-15

x=4+1/5

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