12(1x)=16(x-2)

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Solution for 12(1x)=16(x-2) equation:



12(1x)=16(x-2)
We move all terms to the left:
12(1x)-(16(x-2))=0
We calculate terms in parentheses: -(16(x-2)), so:
16(x-2)
We multiply parentheses
16x-32
Back to the equation:
-(16x-32)
We get rid of parentheses
121x-16x+32=0
We add all the numbers together, and all the variables
105x+32=0
We move all terms containing x to the left, all other terms to the right
105x=-32
x=-32/105
x=-32/105

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