12(1x+5)=3(4x+4)+48

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Solution for 12(1x+5)=3(4x+4)+48 equation: 



12(1x+5)=3(4x+4)+48

We move all terms to the left:

12(1x+5)-(3(4x+4)+48)=0

We add all the numbers together, and all the variables

12(x+5)-(3(4x+4)+48)=0

We multiply parentheses

12x-(3(4x+4)+48)+60=0



We calculate terms in parentheses: -(3(4x+4)+48), so:

3(4x+4)+48

We multiply parentheses

12x+12+48

We add all the numbers together, and all the variables

12x+60

Back to the equation:

-(12x+60)



We get rid of parentheses

12x-12x-60+60=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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