12(2+d)+9d=108

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Solution for 12(2+d)+9d=108 equation: 



12(2+d)+9d=108

We move all terms to the left:

12(2+d)+9d-(108)=0

We add all the numbers together, and all the variables

12(d+2)+9d-108=0

We add all the numbers together, and all the variables

9d+12(d+2)-108=0

We multiply parentheses

9d+12d+24-108=0

We add all the numbers together, and all the variables

21d-84=0

We move all terms containing d to the left, all other terms to the right

21d=84

d=84/21

d=4

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