12(2+m)=6(4m+3)

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Solution for 12(2+m)=6(4m+3) equation: 



12(2+m)=6(4m+3)

We move all terms to the left:

12(2+m)-(6(4m+3))=0

We add all the numbers together, and all the variables

12(m+2)-(6(4m+3))=0

We multiply parentheses

12m-(6(4m+3))+24=0



We calculate terms in parentheses: -(6(4m+3)), so:

6(4m+3)

We multiply parentheses

24m+18

Back to the equation:

-(24m+18)



We get rid of parentheses

12m-24m-18+24=0

We add all the numbers together, and all the variables

-12m+6=0

We move all terms containing m to the left, all other terms to the right

-12m=-6

m=-6/-12

m=1/2

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