12(2-3x)+4x=4(x+2)

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Solution for 12(2-3x)+4x=4(x+2) equation: 



12(2-3x)+4x=4(x+2)

We move all terms to the left:

12(2-3x)+4x-(4(x+2))=0

We add all the numbers together, and all the variables

12(-3x+2)+4x-(4(x+2))=0

We add all the numbers together, and all the variables

4x+12(-3x+2)-(4(x+2))=0

We multiply parentheses

4x-36x-(4(x+2))+24=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

-32x-(4x+8)+24=0

We get rid of parentheses

-32x-4x-8+24=0

We add all the numbers together, and all the variables

-36x+16=0

We move all terms containing x to the left, all other terms to the right

-36x=-16

x=-16/-36

x=4/9

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