12(2-3z)=60

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Solution for 12(2-3z)=60 equation: 



12(2-3z)=60

We move all terms to the left:

12(2-3z)-(60)=0

We add all the numbers together, and all the variables

12(-3z+2)-60=0

We multiply parentheses

-36z+24-60=0

We add all the numbers together, and all the variables

-36z-36=0

We move all terms containing z to the left, all other terms to the right

-36z=36

z=36/-36

z=-1

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