12(2-y)=6(4y-2)

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Solution for 12(2-y)=6(4y-2) equation:



12(2-y)=6(4y-2)
We move all terms to the left:
12(2-y)-(6(4y-2))=0
We add all the numbers together, and all the variables
12(-1y+2)-(6(4y-2))=0
We multiply parentheses
-12y-(6(4y-2))+24=0
We calculate terms in parentheses: -(6(4y-2)), so:
6(4y-2)
We multiply parentheses
24y-12
Back to the equation:
-(24y-12)
We get rid of parentheses
-12y-24y+12+24=0
We add all the numbers together, and all the variables
-36y+36=0
We move all terms containing y to the left, all other terms to the right
-36y=-36
y=-36/-36
y=1

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