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12(2/3)=-1(1/9)y
We move all terms to the left:
12(2/3)-(-1(1/9)y)=0
Domain of the equation: 9)y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-(-1(+1/9)y)+12(+2/3)=0
We multiply parentheses
-(-1(+1/9)y)+2/3*12=0
We calculate fractions
()/9y)*3*12)+18y/9y)*3*12)=0
We can not solve this equation
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