12(2a-7)-20=16a-56

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Solution for 12(2a-7)-20=16a-56 equation: 



12(2a-7)-20=16a-56

We move all terms to the left:

12(2a-7)-20-(16a-56)=0

We multiply parentheses

24a-(16a-56)-84-20=0

We get rid of parentheses

24a-16a+56-84-20=0

We add all the numbers together, and all the variables

8a-48=0

We move all terms containing a to the left, all other terms to the right

8a=48

a=48/8

a=6

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