12(2b+2)=4(6b+1)

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Solution for 12(2b+2)=4(6b+1) equation: 



12(2b+2)=4(6b+1)

We move all terms to the left:

12(2b+2)-(4(6b+1))=0

We multiply parentheses

24b-(4(6b+1))+24=0



We calculate terms in parentheses: -(4(6b+1)), so:

4(6b+1)

We multiply parentheses

24b+4

Back to the equation:

-(24b+4)



We get rid of parentheses

24b-24b-4+24=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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