12(2k-11)=2(2k+12)

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Solution for 12(2k-11)=2(2k+12) equation: 



12(2k-11)=2(2k+12)

We move all terms to the left:

12(2k-11)-(2(2k+12))=0

We multiply parentheses

24k-(2(2k+12))-132=0



We calculate terms in parentheses: -(2(2k+12)), so:

2(2k+12)

We multiply parentheses

4k+24

Back to the equation:

-(4k+24)



We get rid of parentheses

24k-4k-24-132=0

We add all the numbers together, and all the variables

20k-156=0

We move all terms containing k to the left, all other terms to the right

20k=156

k=156/20

k=7+4/5

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