12(2x-1)=8(2x+1)+36

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Solution for 12(2x-1)=8(2x+1)+36 equation: 



12(2x-1)=8(2x+1)+36

We move all terms to the left:

12(2x-1)-(8(2x+1)+36)=0

We multiply parentheses

24x-(8(2x+1)+36)-12=0



We calculate terms in parentheses: -(8(2x+1)+36), so:

8(2x+1)+36

We multiply parentheses

16x+8+36

We add all the numbers together, and all the variables

16x+44

Back to the equation:

-(16x+44)



We get rid of parentheses

24x-16x-44-12=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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