12(2x-11)=3x+(42)

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Solution for 12(2x-11)=3x+(42) equation: 



12(2x-11)=3x+(42)

We move all terms to the left:

12(2x-11)-(3x+(42))=0

We multiply parentheses

24x-(3x+42)-132=0

We get rid of parentheses

24x-3x-42-132=0

We add all the numbers together, and all the variables

21x-174=0

We move all terms containing x to the left, all other terms to the right

21x=174

x=174/21

x=8+2/7

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