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12(2x-3)-(2x-4)=2x+3(x-5)
We move all terms to the left:
12(2x-3)-(2x-4)-(2x+3(x-5))=0
We multiply parentheses
24x-(2x-4)-(2x+3(x-5))-36=0
We get rid of parentheses
24x-2x-(2x+3(x-5))+4-36=0
We calculate terms in parentheses: -(2x+3(x-5)), so:We add all the numbers together, and all the variables
2x+3(x-5)
We multiply parentheses
2x+3x-15
We add all the numbers together, and all the variables
5x-15
Back to the equation:
-(5x-15)
22x-(5x-15)-32=0
We get rid of parentheses
22x-5x+15-32=0
We add all the numbers together, and all the variables
17x-17=0
We move all terms containing x to the left, all other terms to the right
17x=17
x=17/17
x=1
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