12(2x-4)-7(x-4)=14x+3x+22

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Solution for 12(2x-4)-7(x-4)=14x+3x+22 equation:


Simplifying
12(2x + -4) + -7(x + -4) = 14x + 3x + 22

Reorder the terms:
12(-4 + 2x) + -7(x + -4) = 14x + 3x + 22
(-4 * 12 + 2x * 12) + -7(x + -4) = 14x + 3x + 22
(-48 + 24x) + -7(x + -4) = 14x + 3x + 22

Reorder the terms:
-48 + 24x + -7(-4 + x) = 14x + 3x + 22
-48 + 24x + (-4 * -7 + x * -7) = 14x + 3x + 22
-48 + 24x + (28 + -7x) = 14x + 3x + 22

Reorder the terms:
-48 + 28 + 24x + -7x = 14x + 3x + 22

Combine like terms: -48 + 28 = -20
-20 + 24x + -7x = 14x + 3x + 22

Combine like terms: 24x + -7x = 17x
-20 + 17x = 14x + 3x + 22

Reorder the terms:
-20 + 17x = 22 + 14x + 3x

Combine like terms: 14x + 3x = 17x
-20 + 17x = 22 + 17x

Add '-17x' to each side of the equation.
-20 + 17x + -17x = 22 + 17x + -17x

Combine like terms: 17x + -17x = 0
-20 + 0 = 22 + 17x + -17x
-20 = 22 + 17x + -17x

Combine like terms: 17x + -17x = 0
-20 = 22 + 0
-20 = 22

Solving
-20 = 22

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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