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12(3+1x)=5(2x+8)
We move all terms to the left:
12(3+1x)-(5(2x+8))=0
We add all the numbers together, and all the variables
12(x+3)-(5(2x+8))=0
We multiply parentheses
12x-(5(2x+8))+36=0
We calculate terms in parentheses: -(5(2x+8)), so:We get rid of parentheses
5(2x+8)
We multiply parentheses
10x+40
Back to the equation:
-(10x+40)
12x-10x-40+36=0
We add all the numbers together, and all the variables
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
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