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12(3+r)=5(2r+8)
We move all terms to the left:
12(3+r)-(5(2r+8))=0
We add all the numbers together, and all the variables
12(r+3)-(5(2r+8))=0
We multiply parentheses
12r-(5(2r+8))+36=0
We calculate terms in parentheses: -(5(2r+8)), so:We get rid of parentheses
5(2r+8)
We multiply parentheses
10r+40
Back to the equation:
-(10r+40)
12r-10r-40+36=0
We add all the numbers together, and all the variables
2r-4=0
We move all terms containing r to the left, all other terms to the right
2r=4
r=4/2
r=2
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