12(3-(2-2x))+3x=3(9x+5)-3

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Solution for 12(3-(2-2x))+3x=3(9x+5)-3 equation: 



12(3-(2-2x))+3x=3(9x+5)-3

We move all terms to the left:

12(3-(2-2x))+3x-(3(9x+5)-3)=0

We add all the numbers together, and all the variables

12(3-(-2x+2))+3x-(3(9x+5)-3)=0

We add all the numbers together, and all the variables

3x+12(3-(-2x+2))-(3(9x+5)-3)=0



We calculate terms in parentheses: -(3(9x+5)-3), so:

3(9x+5)-3

We multiply parentheses

27x+15-3

We add all the numbers together, and all the variables

27x+12

Back to the equation:

-(27x+12)



We get rid of parentheses

3x+12(3-(-2x+2))-27x-12=0

We add all the numbers together, and all the variables

-24x+12(3-(-2x+2))-12=0

We move all terms containing x to the left, all other terms to the right

-24x+12(3-(-2x+2))=12

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