12(3b+5)=2(24b-3,6)

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Solution for 12(3b+5)=2(24b-3,6) equation: 



12(3b+5)=2(24b-3.6)

We move all terms to the left:

12(3b+5)-(2(24b-3.6))=0

We multiply parentheses

36b-(2(24b-3.6))+60=0



We calculate terms in parentheses: -(2(24b-3.6)), so:

2(24b-3.6)

We multiply parentheses

48b-7.2

Back to the equation:

-(48b-7.2)



We get rid of parentheses

36b-48b+7.2+60=0

We add all the numbers together, and all the variables

-12b+67.2=0

We move all terms containing b to the left, all other terms to the right

-12b=-67.2

b=-67.2/-12

b=5+6/10

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