12(3b-2)=6(b-3)

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Solution for 12(3b-2)=6(b-3) equation: 



12(3b-2)=6(b-3)

We move all terms to the left:

12(3b-2)-(6(b-3))=0

We multiply parentheses

36b-(6(b-3))-24=0



We calculate terms in parentheses: -(6(b-3)), so:

6(b-3)

We multiply parentheses

6b-18

Back to the equation:

-(6b-18)



We get rid of parentheses

36b-6b+18-24=0

We add all the numbers together, and all the variables

30b-6=0

We move all terms containing b to the left, all other terms to the right

30b=6

b=6/30

b=1/5

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