12(3v+1)-6=6(-6-6v)

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Solution for 12(3v+1)-6=6(-6-6v) equation: 



12(3v+1)-6=6(-6-6v)

We move all terms to the left:

12(3v+1)-6-(6(-6-6v))=0

We add all the numbers together, and all the variables

12(3v+1)-(6(-6v-6))-6=0

We multiply parentheses

36v-(6(-6v-6))+12-6=0



We calculate terms in parentheses: -(6(-6v-6)), so:

6(-6v-6)

We multiply parentheses

-36v-36

Back to the equation:

-(-36v-36)



We add all the numbers together, and all the variables

36v-(-36v-36)+6=0

We get rid of parentheses

36v+36v+36+6=0

We add all the numbers together, and all the variables

72v+42=0

We move all terms containing v to the left, all other terms to the right

72v=-42

v=-42/72

v=-7/12

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