12(3x+16)-5(2x-4)=6x-48

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Solution for 12(3x+16)-5(2x-4)=6x-48 equation: 



12(3x+16)-5(2x-4)=6x-48

We move all terms to the left:

12(3x+16)-5(2x-4)-(6x-48)=0

We multiply parentheses

36x-10x-(6x-48)+192+20=0

We get rid of parentheses

36x-10x-6x+48+192+20=0

We add all the numbers together, and all the variables

20x+260=0

We move all terms containing x to the left, all other terms to the right

20x=-260

x=-260/20

x=-13

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