12(3x-1)=10(3x+1)+14

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Solution for 12(3x-1)=10(3x+1)+14 equation: 



12(3x-1)=10(3x+1)+14

We move all terms to the left:

12(3x-1)-(10(3x+1)+14)=0

We multiply parentheses

36x-(10(3x+1)+14)-12=0



We calculate terms in parentheses: -(10(3x+1)+14), so:

10(3x+1)+14

We multiply parentheses

30x+10+14

We add all the numbers together, and all the variables

30x+24

Back to the equation:

-(30x+24)



We get rid of parentheses

36x-30x-24-12=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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